Assuming that the ionic character in H―Br bond is 20 percent. Calculate the fraction of the contribution of the ionic character to the valence bond wave function.

We know that combined wave function is given as:

Ψ AB = Ψcovalent + λΨionic

The percent ionic character is given by:
2/(1 + λ2)] X 100

Therefore, 20 = 100*[λ2/(1 + λ2)]

20 + 20 λ2 = 100λ2
20 = 100λ2 – 20λ2
20 = 80λ2

Therefore, λ2 = 20/80

Hence, λ=(20/80) 1/2= 0.5

Thus, the fraction of contribution of ionic character to Ψ AB is 0.5

Category: Chemical Bonding

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2 Responses to " Assuming that the ionic character in H―Br bond is 20 percent. Calculate the fraction of the contribution of the ionic character to the valence bond wave function. "

  1. arpita ghosh says:

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  2. rashid bwengye says:

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