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Let’s think that we want to calculate the electric field intensity at point p caused by charge q at some point O. So, OP=r. Lets suppose a test charge having positive charge is present at point P. If we apply the coulombs law of forces on ...

The strength of electric field at a particular point is called as Electric Field intensity. In other words, the force felt by a unit positive charge situated at a point is called Electric field intensity. If is the force working on a test charge ...

When a charge q is placed near to any other charge q1 then it feels some force of attraction or repulsion. Hence we can say that the force experienced by the charge q is due to the generation of electric field by charge q1. so ...

As we all know that the charge is always quantized. Pertaining to the smallest amount of charge is that it can exist as +e or –e. It is the charge present on an electron and proton. The total space covered by any charge in dimensions ...

By using this principle we can calculate total amount of force on a given charge due to a number of point charges. According to this principle the total amount of force on a given particle is the vector sum of the individual forces applied on that ...

Suppose two point charges q2 and q1 are located in space at different positions A and B . O is the origin of rectangular co-ordinate system XYZ. This is shown in figure below:-

When the charges are located in some other medium rather than vaccum then the force between the charges will be : --------------- 1.4 Where is the absolute electric permittivity of the medium. The force between the charges held at same distance from each other in vaccum ...

The concept of unit charge can be cleared easily from equation 1.3. Lets suppose r=1m, q1=q2=q and the force F=9 X 10 9. By substititing the values in equation 3 we get: Or So, S.I. unit of charge is Coulomb. Conclusion: When two charges of 1 coulomb each ...

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