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Let’s think that we want to calculate the electric field intensity at point p caused by charge q at some point O. So, OP=r. Lets suppose a test charge having positive charge is present at point P. If we apply the coulombs law of forces on ...

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The strength of electric field at a particular point is called as Electric Field intensity. In other words, the force felt by a unit positive charge situated at a point is called Electric field intensity. If is the force working on a test charge ...

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When a charge q is placed near to any other charge q1 then it feels some force of attraction or repulsion. Hence we can say that the force experienced by the charge q is due to the generation of electric field by charge q1. so ...

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As we all know that the charge is always quantized. Pertaining to the smallest amount of charge is that it can exist as +e or –e. It is the charge present on an electron and proton. The total space covered by any charge in dimensions ...

By using this principle we can calculate total amount of force on a given charge due to a number of point charges. According to this principle the total amount of force on a given particle is the vector sum of the individual forces applied on that ...

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Suppose two point charges q2 and q1 are located in space at different positions A and B . O is the origin of rectangular co-ordinate system XYZ. This is shown in figure below:-

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When the charges are located in some other medium rather than vaccum then the force between the charges will be : --------------- 1.4 Where is the absolute electric permittivity of the medium. The force between the charges held at same distance from each other in vaccum ...

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The concept of unit charge can be cleared easily from equation 1.3. Lets suppose r=1m, q1=q2=q and the force F=9 X 10 9. By substititing the values in equation 3 we get: Or So, S.I. unit of charge is Coulomb. Conclusion: When two charges of 1 coulomb each ...

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